Using d(111)=1.4909897497 nm for MOF-5 (from the preceding plane-spacing calculation) and a CuKa X-ray wavelength of 0.15406 nm, apply Bragg's law 2*d*sin(theta)=n*lambda (n=1) to find the first-order diffraction angle 2*theta. Report the value in degrees to two decimal places. Is this angle larger or smaller than the ZIF-8 (110) angle computed previously, and why?

This is a pure calculation from the stated d-spacing and wavelength; S0004 is attached for structural context. Use n=1 and the exact stated wavelength.